/***********************************
 * Modify this program so that it
 * determines whether an integer
 * entered by the user is positive,
 * zero or negative and prints the
 * result.
 ***********************************/

#include <iostream>

// Function declarations
int main();

// Function definitions
int main() {
    int n{};

    std::cout << "Enter an integer: ";
    std::cin >> n;

    // Modify the following statement so that the
    // program correctly classifies the integer.

    std::cout << n << " is positive." << std::endl;

    return 0;
}









































// Hint:
//
// There are three possibilities, so use a cascading
// conditional statement with two conditions followed
// by a final alternative:
//
//     if ( ... ) {
//         ...
//     } else if ( ... ) {
//         ...
//     } else {
//         ...
//     }









































// Here is one solution:

/*
int main() {
    int n{};

    std::cout << "Enter an integer: ";
    std::cin >> n;

    if ( n > 0 ) {
        std::cout << n << " is positive." << std::endl;
    } else if ( n == 0 ) {
        std::cout << n << " is zero." << std::endl;
    } else {
        std::cout << n << " is negative." << std::endl;
    }

    return 0;
}
*/







































// Do not unnecessarily test a third condition:
//
//     if ( n > 0 ) {
//         std::cout << n << " is positive." << std::endl;
//     } else if ( n == 0 ) {
//         std::cout << n << " is zero." << std::endl;
//     } else if ( n < 0 ) {
//         std::cout << n << " is negative." << std::endl;
//     }
//
// If the first two conditions are false, then we already
// know that
//
//     n <= 0    and    n != 0,
//
// and therefore 'n' must be negative. There is no need
// to test another condition. Simply use an 'else' block.