/***********************************
 * Modify this program so that it
 * determines whether an integer
 * entered by the user is even or
 * odd and prints the result.
 *
 * Be careful about negative
 * integers.
 ***********************************/

#include <iostream>

// Function declarations
int main();

// Function definitions
int main() {
    int n{};

    std::cout << "Enter an integer: ";
    std::cin >> n;

    // Modify the following statement so that the
    // program correctly identifies both even and
    // odd integers.

    std::cout << n << " is even." << std::endl;

    return 0;
}









































// Hint:
//
// You will need to use the remainder operator '%'.
//
// What are the values of n%2 for different values of 'n'?
//
// In particular, try both positive and negative integers.









































// You may have noticed the following:
//
// If 'n' is even, then
//
//     n%2 == 0
//
// regardless of whether 'n' is positive, negative or zero.
//
// If 'n' is odd, then
//
//     n%2 ==  1    if n > 0
//
// and
//
//     n%2 == -1    if n < 0.
//
// Consequently, it is simpler to test whether 'n' is even
// than to test whether it has a remainder of 1.









































// Here is one solution:

/*
int main() {
    int n{};

    std::cout << "Enter an integer: ";
    std::cin >> n;

    if ( n%2 == 0 ) {
        std::cout << n << " is even." << std::endl;
    } else {
        std::cout << n << " is odd." << std::endl;
    }

    return 0;
}
*/