#include <iostream>

// Write a fraction such as
//
//     52134/321
//
// as an integer plus a fraction whose numerator
// is the remainder:
//
//     52134/321 = 162 + 132/321.
//
// If the numerator is exactly divisible by the
// denominator, the remainder is zero. For example,
//
//     91/13 = 7 + 0/13.
//
// Modify the program below so that it displays
// the fraction entered by the user in this form.
//
// You may assume that the user enters a valid
// non-negative integer numerator
//
//     0, 1, 2, 3, 4, ...
//
// and a valid positive integer denominator
//
//     1, 2, 3, 4, ...

// Function declarations
int main();

// Function definitions
int main() {
    int num{};

    std::cout << "Enter a non-negative numerator: ";
    std::cin >> num;

    int den{};

    std::cout << "Enter a positive denominator: ";
    std::cin >> den;

    // Modify this statement to produce the desired output.

    std::cout << num << "/" << den << std::endl;

    return 0;
}









































// Hint:
//
// What are the values of
//
//     52134/321
//
// and
//
//     52134%321
//
// when evaluated using integer arithmetic?
//
// How could you use these two operations to produce
//
//     52134/321 = 162 + 132/321
//
// from the original numerator and denominator?









































// A solution:
/*
int main() {
    int num{};

    std::cout << "Enter a non-negative numerator: ";
    std::cin >> num;

    int den{};

    std::cout << "Enter a positive denominator: ";
    std::cin >> den;

    std::cout << num << "/" << den << " = "
              << (num/den) << " + "
              << (num%den) << "/"
              << den << std::endl;

    return 0;
}
*/