#include <iostream>

/****************************************************************
 * Query the user for two integers, and print all the
 * integers from the first up to or down to and including the
 * second.
 ****************************************************************/

// Function declarations
int main();

// Function definitions
int main() {
    int m{};
    std::cout << "Enter a first integer: ";
    std::cin  >> m;

    int n{};
    std::cout << "Enter a second integer: ";
    std::cin  >> n;

    for ( ; ; ) {
        std::cout << 0 << " ";
    }

    std::cout << std::endl;

    return 0;
}









































// Hint: You will probably need two separate
// for loops and a conditional statement to
// determine which one should execute: one loop
// counts up, while the other counts down.






























/* Both of these solutions work:

int main() {
    int m{};
    std::cout << "Enter a first integer: ";
    std::cin  >> m;

    int n{};
    std::cout << "Enter a second integer: ";
    std::cin  >> n;

    if ( m <= n ) {
        for ( int k{ m }; k <= n; ++k ) {
            std::cout << k << " ";
        }
    } else {
        for ( int k{ m }; k >= n; --k ) {
            std::cout << k << " ";
        }
    }

    std::cout << std::endl;

    return 0;
}

// This solution uses a single for loop. Determine
// why choosing the appropriate value of 'step'
// ensures that the loop always reaches 'n'.

int main() {
    int m{};
    std::cout << "Enter a first integer: ";
    std::cin  >> m;

    int n{};
    std::cout << "Enter a second integer: ";
    std::cin  >> n;

    int step{};

    if ( m <= n ) {
        step = 1;
    } else {
        step = -1;
    }

    for ( int k{ m }; k != n; k += step ) {
        std::cout << k << " ";
    }

    std::cout << n << std::endl;

    return 0;
}
*/