#include <iostream>

/********************************
 * Query the user for two
 * integers, and then calculate
 * and print the sum of all the
 * integers from the smaller to
 * the larger, inclusive.
 ********************************/

// Function declarations
int main();

// Function definitions
int main() {
    int m{};
    std::cout << "Enter a first integer: ";
    std::cin  >> m;

    int n{};
    std::cout << "Enter a second integer: ";
    std::cin  >> n;

    std::cout << "The sum is 0" << std::endl;

    return 0;
}









































// Hint: First ensure that the smaller value
// is stored in 'm' and the larger value in
// 'n'. Then use a for loop and an accumulator
// to calculate the sum.






























/* This is one solution:

int main() {
    int m{};
    std::cout << "Enter a first integer: ";
    std::cin  >> m;

    int n{};
    std::cout << "Enter a second integer: ";
    std::cin  >> n;

    if ( m > n ) {
        // Swap the two values.
        int tmp{ m };
        m = n;
        n = tmp;
    }

    int sum{ 0 };

    for ( int k{ m }; k <= n; ++k ) {
        sum += k;
    }

    std::cout << "The sum is " << sum << std::endl;

    return 0;
}
*/