#include <iostream>

// Query the user for one non-negative integer 'm'
// and draw the pattern shown below.
//
// If m = 5, the output should be
//
//   *************************
//   ****************
//   *********
//   ****
//   *
//
//   *
//   ****
//   *********
//   ****************
//   *************************
//
// If m = 6, the output should be
//
//   ************************************
//   *************************
//   ****************
//   *********
//   ****
//   *
//
//   *
//   ****
//   *********
//   ****************
//   *************************
//   ************************************
//
// Notice that the numbers of asterisks are
// perfect squares. For m = 5, they are
//
//     25, 16, 9, 4, 1, 0, 1, 4, 9, 16, 25.
//
// If m = 0, print one blank line.
//
// If m = 1, print
//
//   *
//
//   *
//
// If the user enters a negative value, simply
// return 0.

// Function declarations
int main();

// Function definitions
int main() {
    return 0;
}



























// Hint:
//
// The number of asterisks on each row follows
// a quadratic pattern:
//
//      2   2   2   2   2   2   2   2   2
//     m , ..., 3 , 2 , 1 , 0 , 1 , 2 , 3 , ..., m
//
// Can you choose a loop variable whose values
// range from -m through m?
//
// If so, how many asterisks should be printed
// when that loop variable has the value 'row'?
//
// Can you solve the entire problem using only
// one loop nested inside another loop?




























// Suppose the outer loop variable 'row' takes
// the values
//
//     -m, ..., -3, -2, -1, 0, 1, 2, 3, ..., m.
//
// The number of asterisks to print is
//
//                    2
//                 row .
//
// There is no need to treat negative values
// differently because, for example,
//
//             2       2
//         (-3)  = (3)  = 9.
//
// What happens when row == 0?
//
// The inner loop executes zero times, but the
// newline is still printed. Thus, the blank
// line in the middle appears automatically.


































// Here is one solution:
/*
int main() {
    int m{};
    std::cout << "Enter a non-negative integer 'm': ";
    std::cin  >> m;

    if ( m < 0 ) {
        return 0;
    }

    for ( int row{ -m }; row <= m; ++row ) {
        for ( int column{ 1 }; column <= row*row; ++column ) {
            std::cout << "*";
        }

        std::cout << std::endl;
    }

    return 0;
}
*/