#include <iostream>

// Query the user for one positive integer 'm'
// and draw an inverted triangle of asterisks
// with 'm' rows.
//
// The first row contains 2*m - 1 asterisks.
// Each subsequent row begins with one additional
// space and contains two fewer asterisks.
//
// For example, if m = 5, the output should be
//
//     ^ *********
//     |  *******
//     5   *****
//     |    ***
//     v     *
//
// If the user enters a value for 'm' that is not
// positive, simply return 0.

// Function declarations
int main();

// Function definitions
int main() {
    return 0;
}



























// Hint:
//
// Like the previous exercise, we must print 'm'
// rows, so the outer loop will look like:
//
//     for ( int row{ 1 }; row <= m; ++row ) {
//
//         // Print the appropriate number of spaces.
//
//         // Print the appropriate number of asterisks.
//
//         std::cout << std::endl;
//     }
//
// Again, each row requires two inner loops. The
// first prints the spaces before the asterisks,
// and the second prints the asterisks.
//
// How many spaces and asterisks should be printed
// on each row?




























// The value of 'row' controls both the number of
// spaces and the number of asterisks.
//
// For example, if m = 5:
//
//     row       spaces       asterisks
//      1         1 - 1           9
//      2         2 - 1           7
//      3         3 - 1           5
//      4         4 - 1           3
//      5         5 - 1           1
//
// Thus, the number of spaces is simply
//
//     row - 1.
//
// The number of asterisks begins at 2*m - 1 and
// decreases by 2 each time 'row' increases by 1.
//
// What formula involving 'm' and 'row' produces
// the values
//
//     2*m - 1, 2*m - 3, 2*m - 5, ..., 1?




























// One formula for the number of asterisks is
//
//     2*m - 2*row + 1,
//
// which can also be written as
//
//     2*(m - row) + 1.
//
// Check this when m = 5:
//
//     row = 1:  2*(5 - 1) + 1 = 9
//     row = 2:  2*(5 - 2) + 1 = 7
//     row = 3:  2*(5 - 3) + 1 = 5
//     row = 4:  2*(5 - 4) + 1 = 3
//     row = 5:  2*(5 - 5) + 1 = 1


































// Here is one solution:
/*
int main() {
    int m{};
    std::cout << "Enter a positive integer 'm': ";
    std::cin  >> m;

    if ( m <= 0 ) {
        return 0;
    }

    for ( int row{ 1 }; row <= m; ++row ) {

        // Print the spaces preceding the asterisks.
        for ( int column{ 1 }; column <= row - 1; ++column ) {
            std::cout << " ";
        }

        // Print the asterisks.
        for ( int column{ 1 };
              column <= 2*(m - row) + 1;
              ++column ) {
            std::cout << "*";
        }

        // The current row is complete.
        std::cout << std::endl;
    }

    return 0;
}
*/