#include <iostream>

// Query the user for one positive integer 'm'
// and draw a triangle of asterisks with 'm' rows.
//
// The first row contains one asterisk, the second
// row contains two asterisks, and so on, with the
// final row containing 'm' asterisks.
//
// For example, if m = 5, the output should be
//
//     ^ *
//     | **
//     5 ***
//     | ****
//     v *****
//
// If the user enters a value for 'm' that is not
// positive, simply return 0.

// Function declarations
int main();

// Function definitions
int main() {
    return 0;
}



























// Hint:
//
// Like the previous exercise, this requires a
// loop within another loop. We must print 'm'
// rows, so the outer loop will look like:
//
//     for ( int row{ 1 }; row <= m; ++row ) {
//
//         // Print the appropriate number of
//         // asterisks for this row.
//
//         std::cout << std::endl;
//     }
//
// Unlike the previous exercise, however, the
// number of asterisks printed in each row is
// not constant:
//
//     row 1:  1 asterisk
//     row 2:  2 asterisks
//     row 3:  3 asterisks
//       ...
//     row m:  m asterisks
//
// How can the value of 'row' be used to control
// the inner loop?




























// The value of 'row' determines how many
// asterisks must be printed on that row.
//
// Thus, the inner loop should count from 1
// through the current value of 'row'.
//
// Notice the difference from the previous
// exercise: the upper bound of the inner loop
// changes each time the outer loop executes.


































// Here is one solution:
/*
int main() {
    int m{};
    std::cout << "Enter a positive integer 'm': ";
    std::cin  >> m;

    if ( m <= 0 ) {
        return 0;
    }

    for ( int row{ 1 }; row <= m; ++row ) {
        for ( int column{ 1 }; column <= row; ++column ) {
            std::cout << "*";
        }

        std::cout << std::endl;
    }

    return 0;
}
*/