#include <iostream>

// In Section 1-7, there was an assignment question that
// asked you to print an improper fraction as a mixed
// number. For example,
//
//     52134/321 = 162 + 132/321
//     91/13 = 7
//
// At that point, you were asked to assume that the
// numerator was non-negative and the denominator was
// positive.
//
// Now that you have learned conditional statements,
// extend that program so that
//
//     - the numerator may be any integer,
//     - the denominator may be any nonzero integer,
//     - a denominator of zero is detected,
//     - the fractional part is not printed when the
//       remainder is zero,
//     - a zero integer part is not printed, and
//     - negative fractions are printed naturally.
//
// For example,
//
//      32/5 = 6 + 2/5
//     -32/5 = -6 - 2/5
//      -4/5 = -4/5
//       4/-5 = -4/5
//     -10/-5 = 2
//
// You may assume that the user enters valid integers.

// Function declarations
int main();

// Function definitions
int main() {
    int num{};

    std::cout << "Enter an integer numerator: ";
    std::cin >> num;

    int den{};

    std::cout << "Enter a nonzero integer denominator: ";
    std::cin >> den;

    std::cout << num << "/" << den << " = "
              << (num/den) << " + "
              << (num%den) << "/"
              << den << std::endl;

    return 0;
}









































// Hint:
//
// In C++, integer division truncates toward zero, and the
// remainder has the same sign as the numerator.
//
// For example, what are the values of
//
//     -11/5
//     -11%5
//
// and what are the values of
//
//     -11/-5
//     -11%-5?
//
// It will be easier to print the answer consistently if
// the denominator is always positive.
//
// If the denominator is negative, how can you use
// assignment to change
//
//     num/den
//
// into an equivalent fraction with a positive
// denominator?









































// If the denominator is negative, multiplying both the
// numerator and denominator by -1 does not change the
// value of the fraction:
//
//      11/-5  becomes  -11/5
//
//     -11/-5  becomes   11/5.
//
// Thus, after checking that the denominator is not zero,
// you can use
//
//     if ( den < 0 ) {
//         num *= -1;
//         den *= -1;
//     }
//
// From that point onward, you only have to consider a
// positive denominator.









































// Try your program with each of the following:
//
//       num    den        output
//
//         0      5        0
//         1      5        1/5
//         4      5        4/5
//         5      5        1
//         6      5        1 + 1/5
//         9      5        1 + 4/5
//        10      5        2
//        11      5        2 + 1/5
//
//        -1      5        -1/5
//        -4      5        -4/5
//        -5      5        -1
//        -6      5        -1 - 1/5
//        -9      5        -1 - 4/5
//       -10      5        -2
//       -11      5        -2 - 1/5
//
//         1     -5        -1/5
//         6     -5        -1 - 1/5
//        -6     -5         1 + 1/5
//
// Also test a denominator of zero.









































// A solution:

/*
int main() {
    int num{};

    std::cout << "Enter an integer numerator: ";
    std::cin >> num;

    int den{};

    std::cout << "Enter a nonzero integer denominator: ";
    std::cin >> den;

    if ( den == 0 ) {
        std::cout << "The denominator cannot be zero."
                  << std::endl;

        return 0;
    }

    std::cout << num << "/" << den << " = ";

    // Make the denominator positive.
    if ( den < 0 ) {
        num *= -1;
        den *= -1;
    }

    if ( num == 0 ) {
        std::cout << "0" << std::endl;
    } else if ( num%den == 0 ) {
        // There is no fractional part.
        std::cout << (num/den) << std::endl;
    } else if ( num < 0 ) {
        // The fraction is negative.

        if ( num/den != 0 ) {
            std::cout << (num/den) << " - ";
        } else {
            // For a proper negative fraction such as
            // -4/5, do not print a zero integer part.
            std::cout << "-";
        }

        std::cout << (-num%den) << "/"
                  << den << std::endl;
    } else {
        // The fraction is positive.

        if ( num/den != 0 ) {
            std::cout << (num/den) << " + ";
        }

        std::cout << (num%den) << "/"
                  << den << std::endl;
    }

    return 0;
}
*/